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robots:armadillo:calibration:welcome [2012/10/11 12:50]
karina
robots:armadillo:calibration:welcome [2012/10/24 11:31]
karina
Line 4: Line 4:
 It is assumed that the turningpoint for the belts is the center of the belts. It is assumed that the turningpoint for the belts is the center of the belts.
  
-  c<sub>l</sub> = 0.00348377 +  cl = 0.00348377 
-  $c_r$ = 0.003193242+  cr = 0.003193242
   w = 1.68336   w = 1.68336
 {{:robots:armadillo:calibration:clockwise_graph.png?350|}} {{:robots:armadillo:calibration:clockwise_graph.png?350|}}
 {{:robots:armadillo:calibration:counterclockwise_graph.png?350|}} {{:robots:armadillo:calibration:counterclockwise_graph.png?350|}}
-==== UMB-mark test ====+===== UMB-mark test =====
  
-{{:robots:armadillo:calibration:calibration_umb.xlsx|UMB}} (168 KB)+{{:robots:armadillo:calibration:calibration_umb.xlsx|UMB}} (168 KB)\\ 
 +{{:robots:armadillo:calibration:paper58.pdf|Paper 58}} (803 KB)\\ 
 +{{:robots:armadillo:calibration:paper59.pdf|Paper 59}} (177 KB)\\ 
 +{{:robots:armadillo:calibration:pos96rep.pdf|pos96rep}} (12.2 MB)
  
 === BEFORE CALIBRATION === === BEFORE CALIBRATION ===
Line 59: Line 62:
  
 $$ \beta = \frac{x_{c.g.,cw}-x_{c.g.,ccw}}{-4L}\cdot \frac{(180^{\circ})}{\pi} $$ $$ \beta = \frac{x_{c.g.,cw}-x_{c.g.,ccw}}{-4L}\cdot \frac{(180^{\circ})}{\pi} $$
-|β = |-235.7484076 cm|+|β = |-235.7484 cm|
 |    |-2.357 m | |    |-2.357 m |
  
Line 68: Line 71:
 $$E_d = \frac{D_R}{D_L} = \frac{R+b/2}{R-b/2} $$ $$E_d = \frac{D_R}{D_L} = \frac{R+b/2}{R-b/2} $$
 |b = |1.524 m| |b = |1.524 m|
-|$E_d$ =|0.9692 |+|$E_d$ =|0.969 |
  
 $$b_{actual} = \frac{90^{\circ}}{90^{\circ}-\alpha}\cdot b_{nominal} $$ $$b_{actual} = \frac{90^{\circ}}{90^{\circ}-\alpha}\cdot b_{nominal} $$
-|$b_{actual}$ =|1.68336|calibrated value of wheelbase|+|$b_{actual}$ =|1.6834|calibrated value of wheelbase|
 | ::: |1.524|before calibration| | ::: |1.524|before calibration|
  
robots/armadillo/calibration/welcome.txt · Last modified: 2021/08/14 04:21 (external edit)